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- From bkweston@lazerlink.com Mon Apr 19 06:56:50 2004
Return-Path: <bkweston@lazerlink.com> X-Sender: bkweston@lazerlink.com X-Apparently-To: colonial-coins@egroups.com Received: (qmail 10845 invoked from network); 19 Apr 2004 13:56:50 -0000 Received: from unknown (66.218.66.216) by m10.grp.scd.yahoo.com with QMQP; 19 Apr 2004 13:56:50 -0000 Received: from unknown (HELO mail.lazerlink.net) (199.234.153.15) by mta1.grp.scd.yahoo.com with SMTP; 19 Apr 2004 13:56:50 -0000 Received: (qmail 23684 invoked by uid 509); 19 Apr 2004 13:55:02 -0000 Received: from unknown (HELO computer) (199.234.152.117) by 0 with SMTP; 19 Apr 2004 13:55:02 -0000 Message-ID: <001801c42615$f9ec5400$a5b7fea9@computer> To: <colonial-coins@yahoogroups.com> Date: Mon, 19 Apr 2004 09:55:29 -0400 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0015_01C425F4.726535E0" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 5.00.2919.6600 X-MIMEOLE: Produced By Microsoft MimeOLE V5.00.2919.6600 X-eGroups-Remote-IP: 199.234.153.15 From: "Byron Weston" <bkweston@lazerlink.com> Subject: V.14-84A X-Yahoo-Group-Post: member; u=90999161 X-Yahoo-Profile: bkweston
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Before we get too far off on a bifurcation, broken A, tangent here is a fol= low-up:
Now - die rotation. There was a Vlack 14-84A in the Montclair=20 hoard. When I cataloged it, I said it had a 10 o'clock die axis -=20 see my AJN article, page 206. The die axis that you show I would=20 call "4 o'clock." Of course, 10 o'clock and 4 o'clock are six hours=20 away from each other, and easily confused, so it's possible that I=20 miscataloged the Montclair piece. There are two of these 14-84As in=20 the ANS, so we'll have to recheck the die axes when we get a chance.
You'll have to ask Gary about that - he currently has it in his possession,= and I simply forget. _________________________________________________
"The reverse die orientation shown in this image is that which you would se= e if you held the obverse of the coin upright and then rotated the coin 180= degrees on its vertical axis.=20=20 Using this convention, a normal coin turn specimen would show the images of= the obverse and reverse both in their upright position. While, with a med= al turn specimen the obverse image would be upright and the reverse would b= e upside down. So, in other words, this specimen has the reverse die rotated approximately= 300 degrees clockwise or 60 degrees counter clockwise with respect to the = obverse."
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD> <META content=3D"text/html; charset=3Dwindows-1252" http-equiv=3DContent-Ty= pe> <META content=3D"MSHTML 5.00.2919.6307" name=3DGENERATOR> <STYLE></STYLE> </HEAD> <BODY bgColor=3D#ffffff> <DIV><FONT face=3DArial size=3D2>Before we get too far off on a bifurcation= , broken=20 A, tangent here is a follow-up:</FONT></DIV> <DIV> </DIV><FONT face=3DArial size=3D2> <BLOCKQUOTE class=3Dcite cite type=3D"cite"><TT>Now - die rotation. T= here=20 was a Vlack 14-84A in the Montclair <BR>hoard. When I cataloged it,= I=20 said it had a 10 o'clock die axis - <BR>see my AJN article, page 206.&nbs= p;=20 The die axis that you show I would <BR>call "4 o'clock." Of course,= 10=20 o'clock and 4 o'clock are six hours <BR>away from each other, and easily= =20 confused, so it's possible that I <BR>miscataloged the Montclair piece.&n= bsp;=20 There are two of these 14-84As in <BR>the ANS, so we'll have to recheck t= he=20 die axes when we get a chance.</TT></BLOCKQUOTE><BR> <DIV>You'll have to ask Gary about that - he currently has it in his posses= sion,=20 and I simply forget.</DIV> <DIV>_________________________________________________</DIV> <DIV> </DIV> <DIV>"The reverse die orientation shown in this image is that which you wou= ld=20 see if you held the obverse of the coin upright and then rotated the coin 1= 80=20 degrees on its vertical axis. <BR>Using this convention, a normal coi= n=20 turn specimen would show the images of the obverse and reverse both in thei= r=20 upright position. While, with a medal turn specimen the obverse image= =20 would be upright and the reverse would be upside down.<BR>So, in other=20 words, this specimen has the reverse die rotated approximately 300 deg= rees=20 clockwise or 60 degrees counter clockwise with respect to the=20 obverse."<BR><BR><BR><BR></DIV></FONT></BODY></HTML>
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